# Line slope calculator 5x-2y=13

**Straight line given by points A[3; 1] and B[5; 6]**

## Calculation:

**Slope-intercept form of line:**y = 2.5x-6.5

**Canonical form of the line equation:**5x-2y-13 = 0

**Parametric form of the line equation:**

x = 2t+3

y = 5t+1 ; t ∈ R

**Slope:**m = 2.5

**Slope angle of line: φ =**68°11'55″ = 1.1903 rad

**X intercept:**x

_{0}= 2.6

**Y intercept:**y

_{0}= q = -6.5

**Distance line from the origin:**d

_{0}= 2.414

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(2; 5)

**Normal vector: n =**(5; -2)

**Midpoint of the segment AB: M =**[4; 3.5]

**Perpendicular Bisector equation:**2x+5y-25.5 = 0

**Vector OA = (3; 1) ; |OA| = 3.1623**

**Vector OB = (5; 6) ; |OB| = 7.8102**

**Scalar product OA .OB = 21**

**Angle ∠ AOB = 31°45'34″ = 0.5543 rad**